甲、乙两车同时从东站开往西站,甲车每小时比乙车多行12千米,甲车行驶4.5小时后到达西站,立即原路返回,
1个回答

设甲车速度每小时x千米,乙车速度每小时x-12千米

4.5+31.5/x = (4.5x-31.5)/(x-12)

31.5/x = (4.5x-31.5)/(x-12)-4.5

31.5/x = (4.5x-31.5-4.5x+54)/(x-12)

31.5/x = 22.5 /(x-12)

31.5x-378=22.5x

9x=378

x = 42

即甲车每小时行42千米