1,
四个不相等的整数a.b.c.d,
-3,-1,1,3,
a+b+c+d=-3-1+1+3=0;
2,
x=10.5时,a=10.5(10.5-1)(10.5-2)...(10.5-20)
x=9.5时,b=9.5(9.5-1)(9.5-2)...(9.5-20)
a+b
=10.5(10.5-1)(10.5-2)...(10.5-20)+9.5(9.5-1)(9.5-2)...(9.5-20)
=10.5(10.5-1)(10.5-2)...(10.5-20)+(10.5-1)(10.5-2)(9.5-2)...(10.5-20)(10.5-21)
=[(10.5-1)(10.5-2)...(10.5-20)][10.5+(10.5-21)]
=[(10.5-1)(10.5-2)...(10.5-20)](21-21)
=[(10.5-1)(10.5-2)...(10.5-20)](0)
=0