高数求积分的问题1.sin根号t/根号t dt的积分
5个回答

Possible intermediate steps:

integral (sin(sqrt(t)))/sqrt(t) dt

For the integrand (sin(sqrt(t)))/sqrt(t),substitute u = sqrt(t) and du = 1/(2 sqrt(t)) dt:

= 2 integral sin(u) du

The integral of sin(u) is -cos(u):

= -2 cos(u)+constant

Substitute back for u = sqrt(t):

= -2 cos(sqrt(t))+constant

简单来说,变量替换

u=根号t