2sin2a - (1/2)cos4a + 3/2
=2sin2a - (1/2)[1 - 2(sin2a)^2] + 3/2
=2sin2a - 1/2 + (sin2a)^2 + 3/2
=(sin2a)^2 + 2sin2a + 1
=(sin2a + 1)^2
=[2sina*cosa + (sina)^2 + (cosa)^2]^2
=[(sina + cosa)^2]^2
=(sina + cosa)^4
等比数列{an}的首项是多少?如果首项是1的话,那2sin2a-1/2cos4a+3/2是数列的第5项.