根据弧长和弦长求半径怎么算?公式我没有看懂!
1个回答

Rn+1=(1+(L-2*Rn*SIN(C/(2*Rn)))/(L-C*COS(C/(2*Rn))))*Rn

取R0,代入上式,得R1

取R1,代入上式,得R2

取R2,代入上式,得R3

.

直到Rn与Rn+1很接近即得R=Rn

弧长900,弦长885;

R0=1500

R1=1407.095

R2=1419.189

R3=1419.453

R3=1419.453

R=1419.453

弧长913,弦长900;

R0=1500

R1=1553.274

R2=1558.423

R3=1558.466

R4=1558.466

R=1558.466

弧长930,弦长900;

R0=1000

R1=1045.885

R2=1051.724

R3=1051.806

R4=1051.806

R=1051.806

弧长918,弦长900;

R0=1000

R1=1180.433

R2=1296.279

R3=1331.664

R4=1334.237

R5=1334.25

R6=1334.25

R=1334.25

弧长932,弦长900;

R0=1000

R1=1020.292

R2=1021.366

R3=1021.369

R4=1021.369

R=1021.369