x^4-x^3-7x^2+13x-6 因式定理法
1个回答

x'4-x'3-7x'2+13x-6

= x³(x-1)-(7x² - 12x + 6)

= x³(x-1)-(7x-6)(x-1)

=(x-1)(x³-7x+6)

=(x-1)(x³-x²+x²-x-6x+6)

=(x-1)【x²(x-1)+ x(x-1)-6(x-1)】

=(x-1)【(x-1)(x²+x-6)】

=(x-1)²(x²+x-6)

=(x-1)²(x+3)(x-2)