2Al+2NaOH+2H2O==2NaAlO2+3H2
2 3
n1 1.68/22.4mol=0.075mol
n1=0.05mol
Al的质量为0.05mol*27g/mol=1.35g,两份为:2.7g
2Al+6HCl==2AlCl3+3H2
Al与盐酸生成的气体也应为1.68L,所以Mg与盐酸生成的气体体积为:2.24-1.68=0.56L
Mg+2HCl==MgCl2+H2
1 1
n2 0.56/22.4=0.025mol
n2=0.025mol
Mg的质量为:0.025mol*24g/mol=0.6g,两份为:1.2g
铜的质量为5g-2.7g-1.2g=1.1g
答:原混合物中铜,镁,铝分别为:1.1g,1.2g,2.7g