甲乙两物体沿着同一条平直公路通向行驶,甲物体以20m/s的速度做匀速直线运动,乙物体原来速度为4米/s,做
1个回答

x=128m,v1=20m/s,v0=4m/s,a=1m/s^2

x1=x0+v1t

x2=v0t+1/2at^2

x1=x2

x0+v1t=v0t+1/2at^2

128+20t=4t+1/2*1*t^2

t^2-32t-256=0

[t-16(1-根号2][t-16(1+根号2)]=0

t1=16(1-根号2)<0,舍去;

t=16(1+根号2)≈38.624s

v=v0+at=4+1*16(1+根号2)=20+16根号2≈42.624m/s