当x=3时,求下列式子的值∶3x+2/x^2-x-2+(1-1/x+1)÷(1+1/x-1)
收藏:
0
点赞数:
0
评论数:
0
1个回答

原式=(3x+2)/(x-2)(x+1)+(x+1-1)/(x+1)÷(x-1+1)/(x-1)

=(3x+2)/(x-2)(x+1)+x/(x+1)÷x/(x-1)

=(3x+2)/(x-2)(x+1)+(x-1)/(x+1)

=(3x+2+x²-3x+2)/(x+1)(x-2)

=(x²+4)/(x+1)(x-2)

=(9+4)/(4×1)

=13/4

点赞数:
0
评论数:
0
关注公众号
一起学习,一起涨知识