微积分: ∫-π/2→π/2(1+cosX )dx.求详解.如题 谢谢了
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∫-π/2→π/2(1+cosX )dx =∫-π/2→π/2(1 )dx+ ∫-π/2→π/2(cosX )dx =x(-π/2→π/2)+sinx(-π/2→π/2) =π/2-(-π/2)+sin(π/2)-sin(-π/2) =π+2 望采纳,学业顺利.

求采纳