(x+y)^2+3(x^2-y^2)+2(x+y)
3个回答

(x+y)²+3(x²-y²)+2(x+y)

=(x+y)²+3(x+y)(x-y)+2(x+y)

=(x+y)[x+y+3(x-y)+2]

=(x+y)(4x-2y+2)

=2(x+y)(2x-y+1)

点拨:x²-y² 应用平方差公式,化为(x+y)(x-y)

再提取每一项公有的(x+y),运用乘法分配律

最后提取(4x-2y+2)中的2,得2(2x-y+1)