因式分解【急死了,1.x²-4xy+4y²-10x+20y+252.(n+1)(n+2)(n+3)(
6个回答

1.x²-4xy+4y²-10x+20y+25

=(x^2-4xy+4y^2)-(10x-20y)+25

=(x-2y)^2-10(x-2y)+25

=(x-2y-5)^2

2.(n+1)(n+2)(n+3)(n+4)+1

=[(n+1)(n+4)][(n+2)(n+3)]+1

=(n^2+5n+4)(n^2+5n+6)+1

=(n^2+5n)^2+10(n^2+5n)+24+1

=(n^2+5n)^2+10(n^2+5n)+25

=(n^2+5n+5)^2

填空题

当x=_______时,代数式x²-4x+10有最小值,最小值是_______

x^2-4x+10=(x^2-4x+4)+6

=(x-2)^2+6

因为(x-2)^2≥0

所以当(x-2)^2=0时,即x=2时,代数式x²-4x+10有最小值,最小值是6