知识问答
最佳答案:#include#includedouble fun1(double x){return sin(x);}double fun2(double x){retur
最佳答案:∫coslnxdx=xcoslnx-∫xdcoslnx=xcoslnx-∫x*(-sinlnx)*1/xdx=xcoslnx+∫sinlnxdx=xcoslnx