(3-2x)(2x+3)+(-3-2x)平方 看补充 计算
1个回答

计算:

(3-2x)(2x+3)+(-3-2x)²

=6x+9-4x²-6x+9+6x+4x²

=18

(x-2y+3)(x+2y-3)

=[x-(2y-3)][x+(2y-3)]

=x²-(2y-3)²

=x²-(4y²-12y+9)

=x²-4y²+12y-9)

分解因式 :

a²(b-2)+b²(2-b)

=a²(b-2)-b²(b-2)

=(2-b)(a²-b²)

=(2-b)(a-b)(a+b)

(4a-3b)²-25b²

=(4a-3b-5b)(4a-3b+5b)

(4a²+b²)³-(4ab)²

=(4a²+b²)³-[3√(4ab)²]³

={(4a²+b²)-[3√(4ab)²]}{(4a²+b²)²+(4a²+b²)[3√(4ab)²]+[3√(4ab)²]²}

(a²-1)²+6(1-a²)+9

=(a²-1)²-6(a²-1)+9

=(a²-1-3)²

=(a²-4)²

=[(a-2)(a+2)]²