1、编写一个程序,将两个Java程序文件显示到屏幕上.
1个回答

1

(1) FileInputStream

(2) char buf;

(3) (char) fis1.read()

(4) while ((buf = (char) fis2.read()) > 0) System.out.print((char) buf);

fis1.close();

(5)catch (FileNotFoundException e)

你题目抄的有点问题 附上可执行源码

public class SequenceInputStreamDemo {

public static void main(String[] args) {

// _______(1)___________fis1,fis2;

FileInputStream fis1,fis2;

try {

fis1 = new FileInputStream("prog1.java");

fis2 = new FileInputStream("prog2.java");

// _________(2)___________;

char buf;

// while((buf=________(3)_________)>0) System.out.print((char)buf);

while ((buf = (char) fis1.read()) > 0) System.out.print((char) buf);

// ________(4)_______;

while ((buf = (char) fis2.read()) > 0) System.out.print((char) buf);

fis1.close();

fis2.close();

// }________(5)_________{

} catch (FileNotFoundException e) {

System.out.println(e);

} catch (IOException e) {

// TODO Auto-generated catch block

e.printStackTrace();

}

}

}

2

(1) 什么也不填

(2) super();

(3) 什么也不填

(4) .indexOf(" ");

(5)i > 0

可执行代码:

public class Name {

private String useName;

private String useS;

// public _______(1)Name{

public Name() {

// _______(2) useName =”whatever”; useS=”whatever”;}

super();

useName = "whatever";

useS = "whatever";

}

// public _______(3)Name (String s)

public Name(String s) {

// {int i=s._______(4)___________;//搜索空格

int i = s.indexOf(" ");

// if(_______(5)___________){

if (i > 0) {

useName = s.substring(0,i);

useS = s.substring(i + 1);

}

}

}