对下列多项式进行因式分解``(1)2X^3+4X^2-6X (2)X^4+6X^2+8(3)X^4+5X^2-36 (4
1个回答

(1)2X^3+4X^2-6X

=2X(X^2+2X-3)

=2X(X+3)(X-1)

(2)X^4+6X^2+8

=(X^4+4X^2+4)+2X^2+4

=(X^2+2)^2+2(X^2+2)

=(X^2+2)(X^2+2+2)

=(X^2+2)(X^2+4)

(3)X^4+5X^2-36

=(X^2+9)(X^2-4)

=(X^2+9)(X+2)(X-2)

(4) X^4-29X^2+100

=(X^2-4)(X^2-25)

=(X+2)(X-2)(X+5)(X-5)

(5)(X^2+3)^2-3(X^2+3)+2

=(X^2+3-1)(X^2+3-2)

=(X^2+2)(X^2+1)

(6)(X^2+X)(X^2+X-2)-3

==(x^2+x+1)(x^2+x-3)

分析:

把x^2+x看成一个整体

比如令x^2+x=t

原式=t(t-2)-3

=t^2-2t-3

=(t+1)(t-3)

把t=x^2+x代回

=(x^2+x+1)(x^2+x-3)