3√2-√2+1/2√2=?
1个回答

√2(√6-√3-√2+1)/√(3-2√2)·√(2-√3)

=√2[√3(√2-1)-(√2-1)] / [√(2-√3)*√(3-2√2)]

=√2(√2-1)(√3-1)*√(2+√3)*√(3+2√2)

=(√2-1)(√3-1)[√2*√(2+√3)]*√[(√2)²+2√2+1]

=(√2-1)(√3-1)[√2*√(2+√3)]*√(√2+1)²

=(√2-1)(√3-1)*√(4+2√3)*(√2+1)

=(√3-1)*√[(√3)²+2√3+1]

=(√3-1)*√(√3+1)²

=(√3-1)*(√3+1)

=2