2x³-2x²-3x=5这个一元三次方程怎么解?
2个回答
用matlab解吧,答案为：
x1=11/(18*((151^(1/2)*216^(1/2))/216 + 26/27)^(1/3)) + ((151^(1/2)*216^(1/2))/216 + 26/27)^(1/3) - 1/3
x2= - 11/(36*((151^(1/2)*216^(1/2))/216 + 26/27)^(1/3)) - ((151^(1/2)*216^(1/2))/216 + 26/27)^(1/3)/2 - 1/3 - (3^(1/2)*(11/(18*((151^(1/2)*216^(1/2))/216 + 26/27)^(1/3)) - ((151^(1/2)*216^(1/2))/216 + 26/27)^(1/3))*i)/2
x3=- 11/(36*((151^(1/2)*216^(1/2))/216 + 26/27)^(1/3)) - ((151^(1/2)*216^(1/2))/216 + 26/27)^(1/3)/2 - 1/3 + (3^(1/2)*(11/(18*((151^(1/2)*216^(1/2))/216 + 26/27)^(1/3)) - ((151^(1/2)*216^(1/2))/216 + 26/27)^(1/3))*i)/2
