2x^4-3x^3-16x^2-3x+2=0 这个方程该怎么解呢,麻烦你了.
4个回答

2x^4-3x^3-16x^2-3x+2=0 x≠0

2x^2-3x-16-3/x+2/x^2=0

2(x^2+1/x^2)-3(x+1/x)-16=0

2(x+1/x)^2-4-3(x+1/x)-16=0

2(x+1/x)^2-3(x+1/x)-20=0

(2x+2/x+5)(x+1/x-4)=0

2x+2/x+5=0,

2x^2+5x+2=0

(2x+1)(x+1)=0

x=-1/2,x=-1

x+1/x-4=0

x^2-4x+1=0

(x-2)^2=3

x-2=±√3

x=2+√3,x=2-√3