初一数学题详细过程1.分解因式 (a-b)的2n-1次方+16(a-b)的2n次方+64(a-b)的2n+1次方2.分解
1个回答

1.分解因式 (a-b)的2n-1次方+16(a-b)的2n次方+64(a-b)的2n+1次方

=(a-b)^(2n-1)+16(a-b)^(2n)+64(a-b)^(2n+1)

=(a-b)^(2n-1)[1+16(a-b)+64(a-b)^2]

=(8a-8b+1)^2*(a-b)^(2n-1)

2.分解因式 4m²(x+y)²-12mn(x+y)(x-y)+9n²(x-y)²

=[2m(x+y)-3n(x-y)]^2

=(2mx-3nx+2my+3ny)^2

3.分解因式x³-18x²+81x

=x(x-9)^2

4.分解因式(x+2y)²+8(x+2y)+16

=(x+2y+4)^2