(x2+3x+12)(x2+7x+12)-120
1个回答

如果是12的话就没有办法分解了,对不起

(X^2+3x+2)(x^2+7x+12)-120

=(x+1)(x+2)(x+3)(x+4)-120

=(X^2+5x+4)(x^2+5x+6)-120

=(X^2+5x+4)^2+2(X^2+5x+4)-120

=(X^2+5x+4+12)(X^2+5x+4-10)

=(X^2+5x+16)(X^2+5x-6)

=(x-1)(x+6)(X^2+5x+16)