设An=1/n+1+1/n+2+1/n﹢3+……+/2n﹙n属于正整数)那么An+1-An=?
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An=1/n+1+1/n+2+1/n﹢3+……+/2nAn+1=1/n+2+1/n+3+...+1/2n+1/2n+1+1/2n+2故An+1-An=1/2n+1+1/2n+2-1/n+1 =1/2n+1-1/2n+2 =1/[(2n+1)(2n+2)]

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