sec50+cot80 谢谢(别叫我用计算器)
1个回答

y=sec50+cot80

=1/cos50+cos80/sin80

=(sin80+sin40cos80)/(sin40sin80)

=[sin40(2cos40+cos80)]/(sin40sin80)

=(2cos40+cos80)/sin80

=[(cos40+cos80)+cos40]/sin80

=(cos20+cos40)/sin80

=2cos30cos10/sin80

=2cos30

=根号3

这其中用到了和差化积的公式.