∫sin(lnx)dx
2个回答

设t=lnx,dt=1/x*dx

∫sin(lnx)dx =∫sint*e^tdt=∫sint*de^t=sint*e^t-∫cost*e^tdt=sint*e^t-∫cost*de^t

=sint*e^t-cost*e^t-∫sint*e^tdt

从而∫sint*e^tdt=(sint*e^t-cost*e^t)/2+C

再把t=lnx代入即得