化简:2a2b24a3b=[b/2a][b/2a];x2−1y•y2x+1=______.
1个回答

解题思路:分式的分子和分母都除以2a2b即可;先分解因式,再约分即可.

2a2b2

4a3b=[b/2a],

x2−1

y•

y2

x+1

=

(x+1)(x−1)

y•

y2

x+1

=y(x-1)

=xy-y,

故答案为:[b/2a],xy-y.

点评:

本题考点: 分式的乘除法.

考点点评: 本题考查了分解因式,分式的乘除运算,约分等知识点的灵活运用.