a+1/a=﹙√a﹚²+﹙1/√a﹚²=4
∴﹙√a﹚²+﹙1/√a﹚²-2=2
∴﹙√a-1/√a﹚²=2
∵0<a<1
∴√a-1/√a<0
∴√a-1/√a=-√2
a+1/a=﹙√a﹚²+﹙1/√a﹚²=4
∴﹙√a﹚²+﹙1/√a﹚²-2=2
∴﹙√a-1/√a﹚²=2
∵0<a<1
∴√a-1/√a<0
∴√a-1/√a=-√2
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