几道运算,(-12)×(6分之1-3分之2+4分之3)-1²-(3分之1-2分之1)÷(-5)(-2)³+2×(-3分之
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(-12)×(6分之1-3分之2+4分之3)

=(-12)×(2/12-8/12+9/12)

=(-12)×3/12

=﹣3

-1²-(3分之1-2分之1)÷(-5)

=1-(2/6-3/6)÷(-5)

=1-1/6×1/5

=1-1/30

=29/30

(-2)³+2×(-3分之1)²÷6分之1

=﹣8+2×1/9÷1/6

=﹣8+2×2/3

=﹣8+4/3

=﹣6(2/3)

x+2(2x-y)-(x+2y)

=x+4x-2y-x﹣2y

=4x﹣4y

=4(x﹣y)

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