怎么化简[(x-2)平方-(X+3分之6-X)]平方,除以[X(X-2)+X+3分之X(X-6)]
2个回答
[(x-2)平方-(X+3分之6-X)]平方,除以[X(X-2)+X+3分之X(X-6)]
=[(x-2)^2-(6-x/x+3)]^2/[X(X-2)+X(X-6)/(x+3)]
=[((x-2)^2(x+3)-(6-x))/(x+3)]^2 / [x((X-2)(x+3)+(X-6))/(x+3)]
=[(x^2-4x+4)(x+3)-(6-x))/(x+3)]^2 / [x(x^2+3x-2x-6+x-6)/(x+3)]
=[(x^3+3x^2-4x^2-12x+4x+12-6+x)/(x+3)]^2 / [x(x^2+2x-12)/(x+3)]
=[(x^3-x^2-7x+6)/(x+3)]^2 / [x(x^2+2x-12)/(x+3)]
=(x^3-x^2-7x+6)^2/(x+3)^2 * (x+3)/x(x^2+2x-12)
=(x^3-x^2-7x+6)^2/(x+3)x(x^2+2x-12)
=(x^3-x^2-7x+6)^2/(x+3)x(x^2+2x-12)
不能继续化简
如题目是
[(x-2)平方-(X+3分之6-X)平方]除以[X(X-2)+X+3分之X(X-6)]
=((x-2)+(6-x/x+3))((x-2)-(6-x/x+3)) /x((x-2)-(6-x/x+3))
=((x-2)+(6-x/x+3)) /x
=((x-2)(x+3)+(6-x)) /x(x+3)
=(x^2+3x-2x-6+6-x) /x(x+3)
=x^2 /x(x+3)
=x /(x+3)
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