(x+2)的四次方+y-1的绝对值=0
(x+2)的四次方=0,y-1的绝对值=0
x=-2
y=1
5xy-【4x²y-(-3xy²+2x²+2x²y)】
=5xy-【4x²y+3xy²+2x²+2x²y】
=5xy-【4x²y+2x²y+3xy²+2x²】
=5xy-【6x²y+3xy²+2x²】
=5xy-6x²y-3xy²-2x²
=5xy-3xy²-6x²y-2x²
=xy(5-3y)-2x²(3y+1)
=-2*1*(5-3*1)-2*(-2)²*(3*1+1)
=-2*2-2*4*4
=-4-32
=-36