初一数学...6.4因式分解的简单应用..解方程..
1个回答

X^2-4X-12=0

(x-6)(x+2)=0

x=6或x=-2

X+2X^2-15=0

(x+5)(x-3)=0

x=-5或x=3

24X-3X^2=0

8x-x^2=0

x(8-x)=0

x=0或x=8

已知(X+Y)^2-2X-2Y+1=0,求2X^2+4XY+2Y^2的值

(x+y)^2-2x-2y+1=0

(x+y)^2-2(x+y)+1=0

(x+y-1)^2=0

x+y=1

2x^2+4xy+2y^2

=2(x^2+2xy+y^2)

=2(x+y)^2

=2*1^2

=2

已知a,b,c为三角形三边,试判断a^2-2ab+b^2-c^2大于0还是小于0还是等于0

a^2-2ab+b^2-c^2

=(a-b)^2-c^2

=(a-b-c)(a-b+c)(根据两边之和大于第三边,a-b-c