编制程序,计算两个复数的减法和乘法.
1个回答

#include

struct Complex{

x05int i;

x05int j;

};

struct Complex subtract(struct Complex,struct Complex);

struct Complex multiply(struct Complex,struct Complex);

void printComplex(struct Complex);

int main(){

x05struct Complex a,b,sub,mul;

x05printf("Input two Complexes:n");

x05scanf("%d %d %d %d",&a.i,&a.j,&b.i,&b.j);

x05sub=subtract(a,b);

x05mul=multiply(a,b);

x05printf("The complexes are respectively ");

x05printComplex(a);

x05printf(" and ");

x05printComplex(b);

x05printf(".nThe difference is ");

x05printComplex(sub);

x05printf(".nThe product is ");

x05printComplex(mul);

}

struct Complex subtract(struct Complex a,struct Complex b){

x05struct Complex c;

x05c.i=a.i-b.i;

x05c.j=a.j-b.j;

x05return c;

}

struct Complex multiply(struct Complex a,struct Complex b){

x05struct Complex c;

x05c.i=a.i*b.i-a.j*b.j;

x05c.j=a.i*b.j+a.j*b.i;

x05return c;

}

void printComplex(struct Complex c){

x05printf("%d",c.i);

x05if(c.j>=0){

x05x05printf("+");

x05}

x05printf("%di",c.j);

}

相关问题