求和cscA secA cotA有关的公式
1个回答

两角和公式

sin(A+B) = sinAcosB+cosAsinB

sin(A-B) = sinAcosB-cosAsinB

cos(A+B) = cosAcosB-sinAsinB

cos(A-B) = cosAcosB+sinAsinB

tan(A+B) = (tanA+tanB)/(1-tanAtanB)

tan(A-B) = (tanA-tanB)/(1+tanAtanB)

cot(A+B) = (cotAcotB-1)/(cotB+cotA)

cot(A-B) = (cotAcotB+1)/(cotB-cotA)

倍角公式

Sin2A=2SinA•CosA

Cos2A=CosA^2-SinA^2=1-2SinA^2=2CosA^2-1

tan2A=2tanA/1-tanA^2

和差化积

sin(a)+sin(b) = 2sin[(a+b)/2]cos[(a-b)/2]

sin(a)-sin(b) = 2cos[(a+b)/2]sin[(a-b)/2]

cos(a)+cos(b) = 2cos[(a+b)/2]cos[(a-b)/2]

cos(a)-cos(b) = -2sin[(a+b)/2]sin[(a-b)/2]

tanA+tanB=sin(A+B)/cosAcosB

积化和差

sin(a)sin(b) = -1/2*[cos(a+b)-cos(a-b)]

cos(a)cos(b) = 1/2*[cos(a+b)+cos(a-b)]

sin(a)cos(b) = 1/2*[sin(a+b)+sin(a-b)]

cos(a)sin(b) = 1/2*[sin(a+b)-sin(a-b

诱导公式

sin(-a) = -sin(a)

cos(-a) = cos(a)

sin(π/2-a) = cos(a)

cos(π/2-a) = sin(a)

sin(π/2+a) = cos(a)

cos(π/2+a) = -sin(a)

sin(π-a) = sin(a)

cos(π-a) = -cos(a)

sin(π+a) = -sin(a)

cos(π+a) = -cos(a)

tanA= sinA/cosA

tan(π/2+α)=-cotα

tan(π/2-α)=cotα

其他非重点三角函数

csc(a) = 1/sin(a)

sec(a) = 1/cos(a)

这都是比较常用的!

天天开心!

sin3a=sin2acosa+cos2asina

=2sinacosacosa+[1-2(sina)^2]sina

=-4(sina)^3+3sina.

cos3a=cos2acosa-sin2asina

=[2(cosa)^2-1]cosa-2sinacosasina

=4(cosa)^3-3cosa.

tan3a=(tan2a+tana)/(1-tan2atana)

=[2tana/(1-(tana)^2)+tana]/[1-29tana)^2/(1-(tana)^2)]

=[3tana-(tana)^3]/[1-3(tana)^2].