五年级数学200道分数脱式计算,带答案过程
1个回答

1题:原式=1/3-1/4+1/4-1/5+1/5-···+1/98-1/99

=1/3-1/99

=32/99

2题:原式=1.2*30*1.09+1.2×67.3

=1.2×(67.3+32.7)

=1.2*100

=120

3题:原式=1.8*40*2.09-1.8*73.6

=1.8*(83.6-73.6)

=1.8*10

=18

4题:原式=4*1.7*8*2.1*19.3*8*4*0.1

=4*8*(1.7*2.1+19.3*0.1)

=32*5

=160

5题:原式=1.2*40*1.08+1.2×56.8

=1.2*(43.2+56.8)

=1.2*100

=120

6题:原式=0.9999×0.7+0.1111*9*0.3

=0.9999*0.7+0.9999*0.3

=0.9999*(0.7+0.3)

=0.9999

1题.经过尝试可发现:1/(3*4)=1/3-1/4,之后所有的都以此类推就ok了.

2到6:思路都一样,找到一个最小公约数,之后把这个数提出来,括号里面多半是10、100这样的数,ok了.

7.2000*1999-1999*1998+1998*1997-1997*1996

=1999*(2000-1998)+1997*(1998-1996)

=1999*2+1997*2

=(1999+1997)*2

=(2000-1+2000-3)*2

=8000-8

=7992

8.(0.75*42.7+57.3-0.573*25)/3*7972

=(0.75*42.7+57.3*1-57.3*0.25)/3*7972

=[0.75*42.7+57.3(1-0.25)]/3*7972

=[0.75*42.7+57.3*0.75]/3*7972

=[(42.7+57.3)*0.75]/3*7972

=75/3*7972

=25*7972

=199300

9./(1*2) + 1/(2*3) + 1/(3*4) + 1/(4*5) + 1/(5*6) + …… + 1/(99*100)

=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+.+1/98-1/99+1/99-1/100

=1-1/100

=99/100

抱歉实在太难找了,这里只有9道.