已知a²-a-4=0,求a²-2(a²-a+3)-1/2(a²-a-4)-a的值
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a²-a-4=0

a²-a=4

a²-2(a²-a+3)-1/2(a²-a-4)-a

=a²-2a²+2a-6-a

=-a²+a-6

=-(a²-a)-6

=-4-6

=-10

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