解
1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)+.1/(x+2012)(x+2013)
=[1/(x+1)-1/(x+2)]+[1/(x+2)-1/(x+3)]+[1/(x+3)-1/(x+4)]+.+[1/(x+2012)-1/(x+2013)]
=1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+1/(x+3)-1/(x+4)+.+1/(x+2012)-1/(x+2013)
=1/(x+1)-1/(x+2013)
=2012/(x+1)(x+2013)
【数学辅导团】为您解答,