博客作业：编程求一元二次方程.ax²+bx+c=0（a≠0）
1个回答
public static void Main()
{
double a,b,c;
Console.Write("a=");
a = Convert.ToDouble(Console.ReadLine());
Console.Write("b=");
b = Convert.ToDouble(Console.ReadLine());
Console.Write("c=");
c = Convert.ToDouble(Console.ReadLine());
Console.WriteLine(a + "x^2+" + b + "x+" + c + "=0");
double d = b * b - 4 * a * c;
double x1,x2;
if (d > 0)
{
x1 = (-b - Math.Sqrt(d)) / 2.0 / a;
x2 = (-b + Math.Sqrt(d)) / 2.0 / a;
Console.WriteLine("方程有两个不同的实根nx1={0}nx2={1}",x1,x2);
}
else if (d == 0)
{
x1 = x2 = (-b) / 2.0 / a;
Console.WriteLine("方程有两个相同的实根nx1={0}nx2={1}",x1,x2);
}
else
{
double i = Math.Sqrt(-d) / 2.0/a;
x1 = x2 = -b / 2.0 / a;
Console.WriteLine("方程有两个复根nx1={0}-{1}inx2={2}+{3}i",x1,i,x2,i);
}
}
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