求一组数值规律(函数)x = 6 ; y = 505x = 7 ; y = 1425x = 11 ; y = 5104x
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我给你写哈

f(6)=505

f(7)=1425

f(11)=5104

f(25)=23975

f(33)=33786

f(40)=42371

f(x)

=42371*[(x-6)(x-7)(x-11)(x-25)(x-33)/(40-6)(40-7)(40-11)(40-25)(40-33)]

+33786*[(x-6)(x-7)(x-11)(x-25)(x-40)/(33-6)(33-7)(33-11)(33-25)(33-40)]

+23975*[(x-6)(x-7)(x-11)(x-33)(x-40)/(25-6)(25-7)(25-11)(25-33)(25-40)]

+5104*[(x-6)(x-7)(x-25)(x-33)(x-40)/(11-6)(11-7)(11-25)(11-33)(11-40)]

+1425*[(x-6)(x-11)(x-25)(x-33)(x-40)/(7-6)(7-11)(7-25)(7-33)(7-40)]

+505 *[(x-7)(x-11)(x-25)(x-33)(x-40)/(6-7)(6-11)(6-25)(6-33)(6-40)]