一.求出函数y＝﹣x²+2x+3
1个回答

y = -(x - 1)² + 4, 对称轴x = 1, 开口向下, 顶点(1, 4)

(1)

x = 1, y = 4

x = 3, y = 0

值域: [0, 4]

(2)

x = -2, y = -5

x = -1, y = 0

x = 0, y = 3

x = 1, y = 4

x = 2, y = 3

值域: {-5, 0, 3, 4}

(3)

y = x²+ 4x:

y = -x² + 4x

y = |x²- 2x|

y = x² - 2|x|

相关问题