73g*10%=7.3g
设碳酸钠的质量为x 则碳酸氢钠的质量为 9.3g-x
Na2CO3+2HCl==2NaCl+H2O+CO2↑
106 73 44
x 73x/106 44x/106
NaHCO3+HCl==NaCl+H2O+CO2↑
84 36.5 44
9.3g-x 36.5*(9.3g-x)/84 44*(9.3g-x)/84
73x/106+36.5*(9.3g-x)/84=7.3g
x=
题目数据有问题呀
73g*10%=7.3g
设碳酸钠的质量为x 则碳酸氢钠的质量为 9.3g-x
Na2CO3+2HCl==2NaCl+H2O+CO2↑
106 73 44
x 73x/106 44x/106
NaHCO3+HCl==NaCl+H2O+CO2↑
84 36.5 44
9.3g-x 36.5*(9.3g-x)/84 44*(9.3g-x)/84
73x/106+36.5*(9.3g-x)/84=7.3g
x=
题目数据有问题呀
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