求不定积分∫[(1+1/x^2)(1-x^2)+xsinx]dx
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∫[(1+1/x^2)(1-x^2)+xsinx]dx

=∫(1/x^2-x^2 + xsinx) dx

= -1/x - 1/3*x^3 +∫xsinx dx

= -1/x - 1/3*x^3 -∫xdcosx

= -1/x - 1/3*x^3 -xcosx + ∫cosx dx

= -1/x - 1/3*x^3 -xcosx + sinx + C

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