2、\x05一底面积40cm x 45cm,高为1cm的木块,质量为5kg,沿涂有润滑油的斜面等速向下运动.已知V=1m
1个回答

润滑油的切应力等于木块重力切向分力:mg sina = μA(du/dy),μ = mg sina (dy/du)/A,

sina=5/13,A=0.4*0.45,dy=0.001,du=1,解得μ = 0.11(Pa*s)