(m+2)^2-9(m-1)^2 (x-y)(x^2+xy+y^2)-xy(y-x)
2个回答

(m+2)^2-9(m-1)^2 平方差

=[(m+2)-3(m-1)][(m+2)+3(m-1)]

=(m+2-3m+3)(m+2+3m-3)

=(5-2m)(4m-1)

(x-y)(x^2+xy+y^2)-xy(y-x)提取公因式

=(x-y)(x^2+xy+y^2)+xy(x-y)

=(x-y)[(x^2+xy+y^2)+xy]

=(x-y)(x^2+xy+y^2+xy)

=(x-y)(x^2+2xy+y^2)完全平方公式

=(x-y)(x+y)^2

3(x-1)^2-18(x-1)+27 提取公因式

=3[(x-1)^2-6(x-1)+9]完全平方公式

=3(x-1-3)^2

=3(x-4)^2

9*1.2^2-16*1.4^2平方差

=(3*1.2-4*1.4)(3*1.2+4*1.4)

=(3.6-5.6)(3.6+5.6)

=-2*9.2

=-18.4