cos10°／tan20°+根号3×tan70°-2cos40°=?
1个回答
cos10°/tan20°+根号3×tan70°-2cos40°
=cos10°/tan20°+2cos30°/tan20°-2cos40°
=(cos10°cos20°+2cos30°cos20°)/sin20°-2cos40°
=(cos10°cos20°+2cos30°cos20°-2cos40°sin20°)/sin20°
=[(cos30°+cos10°)/2+(cos50°+cos10°)-(cos110°+cos30°)]/sin20°
=[(-cos30°+3cos10°)/2+(cos50°+cos70°)]/sin20°
=[(-cos30°+3cos10°)/2+2cos60°cos10°]/sin20°
=[(-cos30°+5cos10°)/2]/sin20°
=[(-cos30°+cos10°)/2]/sin20°+2cos10°/sin20°
=sin20°sin10°/sin20°+2cos10°/sin20°
=sin10°+2sin80°/sin20°
=sin10°+8cos20°cos40°
=sin10°+4(cos60°+cos20°)
=2+sin10°+4cos20°
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