如图11,已知在平面直角坐标系XOY中,A,B分别为OX,OY上两动点,∠B的平分线和∠A的邻补角的平分线交于P
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∠P=180°-1/2∠B-∠BAP

=180°-1/2∠B-(180°-1/2∠A邻补角)

=180°-1/2∠B-(180°-1/2(180°-∠A))

=180°-1/2∠B-(180°-90°+1/2∠A)

=180°-1/2∠B-90°-1/2∠A

=90°-1/2(∠B+∠A)

=90°-45°

=45°