分式计算数学20.22.24
2个回答

20、原式=[4y^2(x+2y)-4x^2y]/(x^2-4y^2)+(x+2y)=-4y(x-2y)(x+y)/(x+2y)(x-2y)+(x+2y)

=[(x+2y)^2-4y(x+y)]/(x+2y)=(x^2+4xy+4y^2-4xy-4y^2)/(x+2y)=x^2/(x+2y)

22、原式=x/x(x+1)*(x+1)(x-1)/(x-1)(x+2)+(x+1)/(x+2)=1/(x+2)+(x+1)/(x+2)=(x+2)/(x+2)=1

24、原式=x(x-y)/x^2*xy/(x+y)(x-y)=x^2y(x-y)/x^2(x+y)(x-y)=y/(x+y)