已知在直角坐标系中,A(0,2),F(-3,0),D为x轴上一动点,过点F作直线AD的垂线FB,交y轴于B,点C(2,
1个回答

以A,B,C,D为顶点的四边形是梯形时,分两种情况:

(1)若AB ∥ CD,则点D 1的坐标为(2,0),如图1;

(2)若AD ∥ BC,设D(x,0),B(0,y).

∵A(0,2),C(2,

5

2 ),AD ∥ BC,

2

-x =

y-

5

2

-2 ,即xy-

5

2 x=4①,

∵AD⊥FB,F(-3,0),

2

-x •

y

3 =-1,即y=

3

2 x②,

②代入①,整理得3x 2-5x-8=0,

解得x 1=-1,x 2=

8

3 .

即点D 2的坐标为(-1,0),D 3的坐标为(

8

3 ,0).

故答案为(2,0)或(-1,0)或(

8

3 ,0).