(x+y)^2-z^=a^2-(b-c)^2=(x-y)^3-x+y=16(x+y)^2-25(x-y)^2=
4个回答

(x+y)^2-z^2

=(x+y+z)(x+y-z)

a^2-(b-c)^2

=(a-b+c)(a+b-c)

(x-y)^3-x+y

=(x-y)^3-(x-y)

=(x-y)[(x-y)^2-1]

=(x-y)(x-y+1)(x-y-1)

16(x+y)^2-25(x-y)^2

=[4(x+y)]^2-[5(x-y)]^2

=[4(x+y)+5(x-y)]*[4(x+y)-5(x-y)]

=(4x+4y+5x-5y)(4x+4y-5x+5y)

=(9x-y)(9y-x)