分解因式(3)-a²+196b²(4)-12xy+x²+36y²
1个回答

(3)-a²+196b²

=196b²-a²

=(14b+a)(14b-a)

(4)-12xy+x²+36y²

=x²-12xy+36y²

=(x-6y)²

(5)a²(a-b)²-b²(a+b)²

=[a(a-b)+b(a+b)][a(a-b)-b(a+b)]

=(a²+b²)(a²-2ab-b²)

(6)(x²-2x)²-1

=(x²-2x+1)(x²-2x-1)

=(x-1)²(x²-2x-1)

化简下列各式

(2)(2-2a)分之(a²-1)*(a²+2a+1)分之(a²+a)

=(a+1)(a-1)/[-2(a-1)]×a(a+1)/(a+1)²

=-a/2

(3) (a-b分之a)²÷(b-a)分之a

=a²/(a-b)²×[-(a-b)/a]

=a/(b-a)

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