log2 1-lg3×log3 2-lg5
2个回答

log₂1-lg3×log₃2-lg5

原式=0-(lg3×log₃2+lg5)

=0-﹙㏒₃3/㏒₃10 ×log₃2 + ㏒₃5/㏒₃10﹚

=0-[1/㏒₃10 (㏒₃2 +㏒₃5)]

=0-(1/㏒₃10 × ㏒₃10)

=0-1

=-1

我们这周的数学试卷上正好也有这一条,顺便帮你一下,一定要给分哦~