求不定积分(*¯︶¯*),
1个回答

设 x = 2sint,则 dx = 2cost*dt

∫x^2*√(4-x^2) *dx

=∫(2sint)^2 * (2cost) * (2cost)*dt

=16*∫(sint)^2 * (cost)^2 *dt

=4*∫(2sint*cost)^2 *dt

=4*∫(sin2t)^2 *dt

=2*∫[2*(sin2t)^2] *dt

=2*∫[1 - cos4t] *dt

=2∫dt - 2∫cos4t*dt

=2t - 1/2*∫cos4t*d(4t)

=2t - 1/2*sin4t + C

=2t - sin2t *cos2t + C

=2t - 2sint*cost*[1 - 2(sint)^2] + C

=2arcsin(x/2) - x/2*√(4 - x^2).*(1-x^2/2) + C